To solve this problem, we need to determine the maximum area of a square that can be formed from a given rectangular tile. The key insight here is that the largest square that fits inside a rectangle will have a side length equal to the shorter side of the rectangle.

Approach

The largest square that can be inscribed in a rectangle with dimensions (L) and (W) has a side length equal to the minimum of (L) and (W). This is because the square cannot exceed the shorter side of the rectangle (otherwise, it would not fit within the rectangle's bounds). The area of this square is then the square of this minimum value.

Solution Code

# Read the dimensions of the rectangle
L, W = map(int, input().split())

# Calculate the maximum square area
max_square_area = min(L, W) ** 2

# Output the result
print(max_square_area)

Explanation

1. Reading Input: The code reads the dimensions (L) (length) and (W) (width) of the rectangle.
2. Finding Minimum Side: The shortest side of the rectangle is found using the min function. This is the side length of the largest possible square.
3. Calculating Area: The area of the square is the square of the shortest side (since area of a square = side × side).
4. Output: The result is printed as the maximum area of the square.

Example: If the rectangle is (5 \times 3), the shortest side is (3), so the area of the largest square is (3^2 = 9). This makes sense because a (3×3) square fits perfectly within the (5×3) rectangle.

This approach efficiently computes the desired result with a time complexity of (O(1)) since it involves basic arithmetic operations and no loops. It is optimal and straightforward.

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