To solve this problem, we need to determine a string where each character is the floor value of the average of the digits in the input string.

Approach

1. Input Reading: Read the input string which consists of digits.
2. Sum Calculation: Compute the sum of all digits in the input string.
3. Average Calculation: Calculate the floor value of the average of the digits (sum divided by the length of the string using integer division).
4. Result Construction: Create a string of the same length as the input, where each character is the floor average digit.

Solution Code

s = input().strip()
total = sum(int(c) for c in s)
length = len(s)
average = total // length
print(str(average) * length)

Explanation

1. Reading Input: The input string is read and stripped of any leading/trailing whitespace.
2. Sum of Digits: We convert each character in the string to an integer and sum these integers to get the total sum of digits.
3. Floor Average: Using integer division (//), we divide the total sum by the length of the string to get the floor value of the average.
4. Result String: We create the result string by repeating the floor average digit exactly as many times as the length of the input string.

This approach efficiently computes the desired result with a time complexity of O(n), where n is the length of the input string, as we process each character once for the sum and then construct the result string.

Examples:

• Input: "123" → Sum = 6 → Average = 6//3 =2 → Output: "222".
• Input: "2345" → Sum=14 → Average=14//4=3 → Output: "3333".

This solution handles all edge cases, including single-digit inputs and inputs with even/odd lengths, correctly.

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